1)If x and y are integers and x*y^2 is a positive odd integer, which of the following must be true?
Ⅰ. xy is positive.
Ⅱ. xy is odd.
Ⅲ. x + y is even.
(A) Ⅰ only
(B) Ⅱ only
(C) Ⅲ only
(D) Ⅰ and Ⅱ
(E) Ⅱ and Ⅲ
2)If a committee of 3 people is to be selected from among 5 married couples so that the committee does not include two people who are married to each other, how many such committees are possible?
A. 20
B. 40
C. 50
D. 80
E. 120
3)Last Sunday a certain store sold copies of Newspaper A for $1.00 each and copies of Newspaper B for $1.25 each, and the store sold no other newspapers that day. If rpercent of the store’s revenues from newspaper sales was from Newspaper A and if ppercent of the newspapers that the store sold were copies of newspaper A, which of the following expresses r in terms of p?
A. 100p / (125 – p)
B. 150p / (250 – p)
C. 300p / (375 – p)
D. 400p / (500 – p)
E. 500p / (625 – p)
4)Alice's take home pay last year was the same each month and she saved the same fraction of her take home pay each month.The total amount of money that she had saved at the end of the year was 3 times the amount of that portion of her monthly take home pay that she did not save. If all the money that she saved last year was from her take home pay, what fraction of her take home pay did save each month.
A 1/2
B 1/3
C 1/4
D 1/5
E 1/6
5)A certain university will select 1 of 7 candidates eligible to fill a position in the mathematics department and 2 of 10 candidates eligible to fill 2 identical positions in the computer science department. If none of the candidates is eligible for a position in both departments, how many different sets of 3 candidates are there to fill the 3 positions?
A. 42
B. 70
C. 140
D. 165
E. 315
6)On Saturday morning, Malachi will begin a camping vacation and he will return home at the end of the first day on which it rains. If on the first three days of the vacation, the probability of rain on each day is 0.2, what is the probability that Malachi will return home at the end of the day on the following Monday?
(A) 0.008
(B) 0.128
(C) 0.488
(D) 0.512
(E) 0.640
7)The perimeter of a certain isosceles right triangle is 16+16 sqr root 2.
What is the lenght of the hypotenuse of the triangle.
A 8
B 16
C 4 sqr root 2
D 8 sqr root 2
E 16 sqr root 2
8)The sum of three integers is 40. The largest integer is 3 times the middle integer, and the smallest integer is 23 less than the largest integer. What is the product of the three integers?
A. 1,104
B. 972
C. 672
D. 294
E. 192
9)If n is a multiple of 5 and n=p^2q, where p and q are prime numbers, which of the following must be a multiple of 25?
(a) p^2
(b) q^2
(c) pq
(d) p^2q^2
(e) p^3q
10)The number 75 can be written as the sum of the squares of 3 different positive intergers.What is the sum of these 3 integers.
a 17
b 16
c 15
d 14
e 13
Official answers will be posted by friday. Post/Discuss the answers using comment option. Here is a comparison chart to gauge your performance
| Correct | Remarks |
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| 7-8 | Above Average |
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Posts
1e,2e,3d,4d,5e,6b,7b,8b,9d,10e
ReplyDelete1e,2d,3d,4d,5e,6b,7d,8b,9d,10e
ReplyDelete@anonymous and Yari
ReplyDeleteyou both got one wrong. I will post the OAs this friday.
Thanks,
Quant-Master
Saurabh: 1e,2b,3d,4d,5e,6b,7b,8b,9d,10e
ReplyDeleteI am guessing that Yari errorounesly posted 'd' against Q7.
1e, 2d, 3d, 4d, 5e, 6b, 7b, 8b, 9d, 10e
ReplyDelete@ saurabh, the answer for 2, is definitely 80 or d;
ReplyDelete10 * 8 * 6 = 480. 480/3! = 80
This comment has been removed by the author.
ReplyDelete1e;2d;3e;4c;5e;6d;7d;8b;9c;10e
ReplyDeleteThe answer for 9 is d.I typed it wrong
ReplyDeleteOA will be posted tomorrow.
ReplyDeleteThanks,
Quant-Master
1e, 2?, 3?, 4d, 5e, 6b, 7b, 8b, 9?, 10e
ReplyDeleteHere is the OA.
ReplyDelete1)E
2)D
3)D
4)D
5)E
6)B
7)B
8)B
9)D
10)E
Let me know the questions for which you require detailed explanations.
Thanks,
Quant-Master
I got all right!! guy at no. 5
ReplyDeleteWhere are the explanations to these problems ?
ReplyDeleteHi Malay,
ReplyDeleteLet me know the questions to which you need explanations. I will post it for you.
Thanks,
Quant-Master
Hi GMAT ... Please post the answers to 2,3,4,5
ReplyDeleteQuestion 2 can be solved in 2 ways:
ReplyDeleteapproach 1) Go by cases
a) 3 men only
no. of ways = 5C3 = 10
b) 3 women only
no. of ways = 5C3 = 10
c) 2 men and 1 woman
no. of ways = 5C2 * 3C1 = 30
d) 2 women and 1 man
no. of ways = 5C2 * 3C1 = 30
so total ways = 10+10+30+30 = 80
Approach 2: tricky and risky
Out of the 10 people available you can select 1 in 10 ways.
Now out of the 9 remaining people delete one person who is the spouse of already selected person, now you can select 2nd person in 8 ways.
Similarly delete the spouse of 2nd selected person now you can select 3rd person in 6 ways.
Hence number of ways = 10*8*6/3! = 80
We divide by 3! because the above case we considered is an arrangement but the problem at issue is selection. Selecting 1st, 2nd and 3rd person is same as selecting 2nd, 3rd and 1st person. To remove duplication we divide by 3!
Let me know if you have any queries
Thanks,
Quant-Master
Response to Question 3:
ReplyDeleteTotal no.of copies sold = Copies of A + Copies of B------ (1)
Total revenues = Revenue of A + Revenue of B --------(2)
Copies sold = a+b
Revenues= 1*a + 1.25*b
So , Percentage of copies "A" sold = a/(a+b) *100 = p
percentage of revenue from A is = a/(a+1.25b) = r
Now try to substitute P in different options and you will find that only D satisfies.
Thanks,
Quant-Master
Response to Question 4:
ReplyDeleteLet A save x per month
hence in 12 months A saves 12x
Let A spend y per month
The total amount of money that she had saved at the end of the year was 3 times the amount of that portion of her monthly take home pay that she did not save.
hence 12x = 3y
x/y = 1/4
Hence A's total pay is x+y = 5
she saved x/x+y = 1/5
Thanks,
Quant-Master
Response to Question 5:
ReplyDeleteThis is one of the easiest question presented in difficult way.
Selecting one out of 7 candidates is 7c1 = 7 ways---(1)
selecting two out of 10 candidates is 10c2 = 45 ways---(2)
Since selecting involves filling a position in math department AND computer science dept we multiply (1) & (2)
7*45 = 315
Hence E
Let me know if you have any queries
Thanks,
Quant-Master
Hey GMAT ,
ReplyDeleteIn 5 , I also got 315 , but had a doubt . In selecting 2 out of 10 , we can AB as well as BA . SO they will be same !! So dont we need to divide the number of ways by 2 ?
Hi Malay,
ReplyDeleteI guess you are confusing selection with arrangement. When we say 7c1 or 10c2 I am selecting one out of 7 or selecting 2 out of 10. Selecting AB is same as BA and this is not accounted twice in 10c2. If you are still not sure have a look at the below example
Selecting two out of A, B and C can be done in 3c2 ways = 3 ways (AB, AC, BC). Here 3c2 will consider AB and BA as same.
Hope I am clear.
Let me know if you need further assistance
Thanks,
Quant-Master
Pl would you explain about Problem No. 9.
ReplyDeleteThanks in advance.