Wednesday, August 5, 2009

Question of the day - 4th August, 2009 - Bonus

The Question:

Mixture A is 15 percent alcohol, and mixture B is 50 percent alcohol. If the two are poured together to create a 4-gallon mixture that contains 30 percent alcohol, approximately how many gallons of mixture A are in the mixture?

  1. 1.5

  2. 1.7

  3. 2.3

  4. 2.5

  5. 3.0
Discuss your answers using comment option. OA will be posted in 24 hrs time

Thanks,
Quant-Master

4 comments:

  1. The answer is C, 2.3

    If
    quantity of A=x gallons
    and
    quantity of B=y gallons

    Then,
    Total volume of mixture= x+y=4 --------(1)
    Total amount of alcohol in the mixture=
    15x/100+50y/100=30/100(x+y)=30*4--------(2)

    To be able to solve linear equations involving multiple variable, we must have as many equations as the variables.

    Here, we have two variables and two equations

    Solving (1) and (2) for x gives x=2.27~2.3
    and hence the answer is C

    ReplyDelete
  2. I know :) :P
    By the way, you haven't posted answers to any of the questions you've been giving out everyday :|

    ReplyDelete
  3. Check the comments under each question. I have posted answers to all the questions. After I post a question I give a gap of 24 hrs to post solution.

    Thanks,
    Quant-Master

    ReplyDelete