Wednesday, August 5, 2009

Question of the day - 4th August, 2009

Question 1

If xyz ≠ 0, is x (y + z) ≥ 0?

(1) |y + z| = |y| + |z|
(2) |x + y| = |x| + |y|

Question 2

How many different prime factors does N have?

(1) 2N has 4 different prime factors.
(2) N ^2 has 4 different prime factors.

Answers will be posted in 24 hrs. Check back for detailed explanation

Thanks,
Quant-Master

8 comments:

  1. Solution to Question 1:

    For x(y+z) to be greater than or equal to zero x should be +ve and y+Z should also be +ve or x should be -ve and y+z should also be -ve

    from statement 1 we can infer that y and z both are of same sign. Try different numbers if you are not sure

    from statement 2 we can infer that x and y both are of same sign. Try different numbers if you are not sure

    Hence x and y+z are of same sign. When you multiply to numbers of same sign you get an +ve number Hence C

    Thanks
    Quant-Master

    ReplyDelete
  2. Solution to Question 2:

    This is best explained by example

    Statement 1:2N has 4 different prime factors.

    case i)Lets say the number N is 2*3*5*7 it has 4 different prime factors now 2N will be 2^2*3*5*7 still 4 different prime factors
    case ii) Lets say the Number N is 3*5*7, it has 3 different prime factors now 2N will be 2*3*5*7 which means now the prime factors have changed from 3 to 4.

    Hence from statement 1 it can be either 3 or 4 factors (insufficient)

    Statement 2: N ^2 has 4 different prime factors.

    After squaring a number N which has n prime factors will still have n prime factors only.
    Example N= 2*3*5*7
    N^2 = 2^2*3^2*5^2*7^2

    which still has 4 prime factors hence statement B alone is sufficient

    Hence B

    Thanks,
    Quant-Master

    ReplyDelete
  3. It would be nice if you explain bit elaborately.

    Thanks

    ReplyDelete
  4. Let me know to which question you need elaborate explanation.

    Thanks,
    Quant-Master

    ReplyDelete
  5. Hi GMAT,

    I have been struggling with the concept of
    |x| - |y| gt or lt |x-y|
    I remember u mentioning some funda that for the above eqn to hold true |y| > |x| and x and y should be of the same sign.

    Can you take it up a little bit.

    ReplyDelete
  6. @ anonymous

    Let's start from scratch

    |x| means no matter what the symbol of x be, by placing modulus(||)it becomes positive.

    (1) |y + z| = |y| + |z|

    Now in the RHS of the above eqn, by placing modulus to both y and z we have made them +ve (same sign).

    Now take LHS, either y and z should be +ve to equal with RHS or both should be -ve. If both are negative we can write LHS as |-(y+z)| and finally this will be nothing but |y+z| coz of modulus symbol.

    Let me know if you need further explanation.

    Thanks,
    Quant-Master

    ReplyDelete
  7. Hi GMAT,

    So from your explanation can I assume that, y and z should have the same sign because otherwise, the values on LHS and RHS will not be the same?

    ReplyDelete
  8. yes John. That's the only way to satisfy the equation

    Thanks,
    Quant-Master

    ReplyDelete