Friday, August 21, 2009

Question of the day - 22nd August, 2009

In a certain game played with red chips and blue chips, each red chip has a point value of X and each blue chip has a point value of Y, where X>Y and X and Y are positive integers. If a player has 5 red chips and 3 blue chips, what is the average (arithmetic mean ) point value of the 8 chips that the player has?


(1) The average point value of one red chip and one blue chip is 5.
(2) The average point value of the 8 chips that the player has is an integer.

OA will be posted soon.

Thanks,
Quant-Master

10 comments:

  1. IMO E. Not sure though.
    Qn: (5r+3b)/8

    (1) (2r+3*5) / 8. Not sufficient
    (2) Not Sufficient alone

    Together, the eqn in (1) can never be even.

    So effectively I either got the answer or screwed it up royally :P

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  4. Ans is C

    1)(X+Y)/2=5 => X+Y=10 --> Not alone sufficient
    2)(5X + 3Y)/8 =?? (Integer) --> Not alone sufficient

    3) Both together
    Subsituting X=10-Y in second equation:
    => (5(10-Y)+3Y)/8 = Z, where Z is an Integer
    => 50-2Y should be multiple of 8

    If Y=1 => 50-2Y=48 (multiple of 8, so one option)
    Y=2 => 50-2Y=46 (not a multiple of 8, can't be the answer)
    Y=3 => 50-2Y=44 (not a multiple of 8, can't be the answer)
    Y=4 => 50-2Y=42 (not a multiple of 8, can't be the answer)

    Y cannot be greater than 4 as X>Y, hence X=9 and Y=1
    => arithmetic mean
    = ((5*9 + 3*1))8 = 8

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  5. Amit - C is the answer

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  6. Thanks a lot for your questions and concepts...I gave my GMAT on Saturday and got a 730 :)

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  7. @ Che'

    well done! nice to hear that. Let me know if you need guidance for further steps

    Thanks,
    Quant-Master

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  8. Explanation from Neeraj looks fine.

    Let me know if somebody needs further explanation.

    Thanks,
    Quant-Master

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  9. Hi,

    Can you please point out the mistake in my analysis?

    --
    Hungry

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  10. @ Hungry

    I don't understand the first equation formed by you. I guess you went wrong in the first equation. Also in the second eqn it would be better if you can list out various possible answers.

    Thanks,
    Quant-Master

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