If x is an integer, is y an integer?
(1) The average (arithmetic mean) of x, y and y – 2 is x.
(2) The average (arithmetic mean) of x and y is not an integer.
(1) The average (arithmetic mean) of x, y and y – 2 is x.
(2) The average (arithmetic mean) of x and y is not an integer.
Question 2:
Three types of pencils, J,K, and L, cost $0.05, $0.10, and $0.25 each, respectively. If a box of 32 of these pencils costs a total of $3.40 and if there are twice as many K pencils as L pencils in the box, how many J pencils are in the box?
(A) 6
(B) 12
(C) 14
(D) 18
(E) 20
(A) 6
(B) 12
(C) 14
(D) 18
(E) 20
Question 3:
Forty percent of the rats included in an experiment were male rats. If some of the rats died during the experiment and 30 percent of the rats that died were male rats, what was the ratio of the death rate among the male rats to the death rate among the female rats?
(A) 9/14
(B) 3/4
(C) 9/11
(D) 6/7
(E) 7/8
(A) 9/14
(B) 3/4
(C) 9/11
(D) 6/7
(E) 7/8
OA will be posted soon.
Thanks,
Quant-Master
Question:1 A.
ReplyDeleteQuestion:2 C.
Question:3 A.
Question:1 D.
ReplyDeleteQuestion:2 C.
Question:3 didn't get the Q
Response to Question 1:
ReplyDeletestatement 1: (x+y+y-2)/3 = x
x+2y-2=3x
2y-2 = 2x
y-1 = x
Since x is an integer Y is also an integer. Sufficient
Statement 2 is insufficient
Response to Question 2:
Let number of L pencils be x
then number of K pencils be 2x
and let number of J pencils be y
so y+3x = 32
and 5*y + 10*2x + 25*x = 340
y+9x = 68
solving these eqns we get x = 6 and y = 14
so the J pencils are 14.
Hence C
Response to Question 3:
Let total number of rats = 1000
male = 400 and female = 600
let percentage of rats which died = x
0.3x = male rats and 0.7x = female rats
required ratio = rate of male deaths / rate of female deaths =
(0.3x / 400)/(0.7x / 600) = 18/28 = 9/14
Hence A
I will solve Q2 in a different way. I first check quickly which of the answers fulfill
ReplyDelete32-J=3L (L must be an integer).
(a) 32-6=26 (wrong)
(b) 32-12=20 (wrong)
(c) 32-14=18 (possible)
(d) 32-18=14 (wrong)
(e) 32-20=12 (possible)
Further check
If J=14, then K=12, L=6;
14*0.05+12*0.1+6*0.25
=0.7+1.2+1.5
=3.40 (nailed)
1. A
ReplyDelete2. C
3. A
Pls post the OA's.
OAs already posted. See comment#3
ReplyDelete