Thursday, August 20, 2009

Question of the day - 21st August, 2009

Question.1:

If x and y are positive, is x^3 > y

(1)square root of x >y
(2)x > y

Question.2:

Material A costs $3 per kilogram, and material B costs $5 per kilogram. If 10 kilograms of material K consists of x kilograms of material A and ykilograms of material B, is x > y?

(1) y > 4
(2) The cost of the 10 kilograms of material K is less than $40.

Answers will be posted in the blog after 12 hrs.

Thanks,
Quants-Master

3 comments:

  1. Qn 1. E
    (1) If x and y is less than 1 and root[x]>y then, cube[x] can be less than y.
    If x and y is greater than 1 and root[x]>y then, cube[x] will be greater than y.

    Not sufficient.

    (2) Same explanation as 1. Consider the case of x and y less than 1.
    e.g: x = 0.9 and y = 0.8

    Qn 2. B

    (1) Is y greater than x? y can be 4 where x will be 6 and y can be 6 when x will be 4. Not Sufficient.

    (2) Considering y=5 and x=5, the value will be $40. But the value should be less than $40 according to the question. If y = 4 and x = 6, then the value will be $12+$30 = $42 (Not acceptable). So, consider y = 6 and x = 4, value will be $18+$20 = $38.

    So answer is y > x. Solution (2) is sufficient.
    Am I right?

    ReplyDelete
  2. Response to Question #1:

    Ans is E

    1. not sufficient. different answers for fractions and integers. Try (0.5 and 3 as example)
    2. not sufficient. different ans for fractions and integers Try (any number of above kind)

    1&2 Together

    x>y and sqrt x>y. No way to differentiate whether x is a integer or fraction as we don't know whether x greater or less than sqrt (x)



    Response to Question #2:

    Ans B

    Statement 1 is not suff. case 5,5 and 4,6 gives diff ans.

    Statement 2 says cost of 10 KG of material is less than $40. If we take X and Y as 5 the amount is $40. So the amount to be less than this $5 material should definitely be less than $3 material. Hence Sufficient

    Thanks,
    Quant-Master

    ReplyDelete
  3. You are perfect Hungry

    Thanks,
    Quant-Master

    ReplyDelete