I was heading to post “How to find the last two digit of a number that appears in weird form say 37^234566” then I realized I am yet to post “How to find unit digit of a number”!! So stupid of me:D
Okay! Let’s get on with the business:
First let me ask you few questions. If I ask you to find unit digit of the below mentioned numbers, how comfortable you are?
31^167535
6756425^243538
200019182^266435483
Very comfortable
Comfortable
Not that comfortable
Not comfortable at all
If you selected any of the last two options then read on!!
Well, for all the three questions I posted above I just typed the numbers as my finger went. I never bothered what number I am typing. Know why? Because no matter what the number is we approach it in very much the same way.
Let’s get on with the work now!!
All the numbers have its cycles. You should know that to proceed further
If we take the number 1: 1 raised to any power will have unit digit 1. This also holds true for any number that ends in 1. Example 41^x, 5011^x, 611^x etc will have unit digit as 1.
Now you have the answer for the first question I posted. Unit digit of 31^167535 ??
It’s 1 of course.
Same property applies for 0, 5 and 6. Any number that ends in 0, 5 or 6 will have same unit digit.
What if I get any other number which is not mentioned above? How do I find unit digit?
Here it is how:
Let’s take the cycles of each number and try to analyze them
Let’s take 2 :
2^1 is 2
2^2 is 4
2^3 is 8
2^4 is 16
2^5 is 32
2^6 is 64
Now if you notice the unit digit is repeating after the power 4. So the cycle of 2 is 2, 4, 8, 6.
Hence cycle can be expressed in 4k form. Why should I take it in 4k form? Here is why
Find the unit digit of 2^1676.
1676 is a multiple of 4. Hence 1676 can be expressed as 4k. Therefore 2^4k will have unit digit as 6.
Let’s take another example 132^1233.
Forget how big the number is. Just consider 2^1233. 1233 when divided by 4 will give a remainder of 1. Hence it is of the form 4k+1. When the number is of the form 4k+1 it means a cycle of 4 is complete and hence the first number of the cycle will be its unit digit which is 2.
Now you should have answers to all my questions posted above
Try these numbers and post the answer using comment option
Find the unit digit of
1230^56909374
122255^3279495763
7865436^129084645
1232^1201
18972^1223
9874562^1782
Once you are clear with this, based on your response, I will post the approach to find unit digit of numbers ending in 3,4,7,8 and 9.
Thanks,
Quant-Master
Correct me if I'm wrong
ReplyDelete1. 0
2. 5
3. 6
4. 2
5. 8
6. 4
bingo! you got all of them correct Andz
ReplyDeleteLet me know if you have any queries
Thanks,
Quant-Master
Great tips. Thanks.
ReplyDeletecan u explain me how u get the unit digit of 9874562^1782 as 2 .acc to me 1782 is in the form of 4k so v shd get 6 as unit digit
ReplyDeletepls tell me the approach of finding unit digit of number ending with 3,4,7,8 and 9.
ReplyDelete